( √24 + √216 )/√96 = ?
⇒ ( √24 + √216 )/√96 = [ √( 2 × 2 × 2 × 3 ) + √( 3 × 3 × 3 × 2 × 2 × 2 )/√( 2 × 2 × 2 × 2 × 2 × 3 )

सही विकल्प: B

( √24 + √216 )/√96 = ?
⇒ ( √24 + √216 )/√96 = [ √( 2 × 2 × 2 × 3 ) + √( 3 × 3 × 3 × 2 × 2 × 2 )/√( 2 × 2 × 2 × 2 × 2 × 3 )
= [ 2√6 + 6√6 ]/4√6 = 8√6/4√6 =2
∴ ? = 2
अतः ? के स्थान पर 2 होगा ।

( 52 )² - ( 7 )³ × 12 = ? × 4
∴ ? = [ ( 52 )² - ( 7 )³ × 12 ]/4

सही विकल्प: C

( 52 )² - ( 7 )³ × 12 = ? × 4
∴ ? = [ ( 52 )² - ( 7 )³ × 12 ]/4
= ( 2704 - 4116 )/4 = -1412/4 = -353
∴ ? = -353
अतः ? के स्थान पर ( -353 )होगा ।

∛1331 × ∛216 + ∛729 + ∛64 = ?
∴ ∛1331 × ∛216 + ∛729 + ∛64

सही विकल्प: B

∛1331 × ∛216 + ∛729 + ∛64 = ?
∴ ∛1331 × ∛216 + ∛729 + ∛64 = ∛( 11 × 11 × 11 ) × ∛( 2 × 2 × 2 × 3 × 3 × 3 ) + ∛( 3 × 3 × 3 × 3 × 3 × 3 ) + ∛( 2 × 2 × 2 × 2 × 2 × 2 )
= 11 × 6 + 9 + 4 = 79
∴ ? = 79
अतः इसका मान 79 होगा ।

∵ [ 3.2 × 5.4 ]/( 0.3 )³ = ?
⇒ ? = [ 3.2 × 5.4 ]/( 0.3 )³ = [ 3.2 × 5.4 ]/( 0.3 ) × ( 0.3 ) × ( 0.3 )

सही विकल्प: B

∵ [ 3.2 × 5.4 ]/( 0.3 )³ = ?
⇒ ? = [ 3.2 × 5.4 ]/( 0.3 )³ = [ 3.2 × 5.4 ]/( 0.3 ) × ( 0.3 ) × ( 0.3 )
⇒ ? = [ 32 × 54 ] x 10 / ( 3 × 3 × 3 ) = 32 × 2 × 10
∴ ? = 640
अतः इसका मान 640 होगा ।

∵ ∛0.002197 = ?
∴ ∛0.002197 = ∛( 2197/1000000 ) = ∛2197/100
⇒ 2197 = 13 × 13 × 13
∴ ∛2197/100 = ∛( 13 × 13 × 13 )/100 = 13/100 = 0.13
∴ ∛0.002197 = 0.13

सही विकल्प: A

∵ ∛0.002197 = ?
∴ ∛0.002197 = ∛( 2197/1000000 ) = ∛2197/100
⇒ 2197 = 13 × 13 × 13
∴ ∛2197/100 = ∛( 13 × 13 × 13 )/100 = 13/100 = 0.13
∴ ∛0.002197 = 0.13
अतः इसका घनमूल 0.13 होगा |